(-v^2+5v-6)=(7v^2+4v+3)

Solution for (-v^2+5v-6)=(7v^2+4v+3) equation:

(-v^2+5v-6)=(7v^2+4v+3)

We move all terms to the left:

(-v^2+5v-6)-((7v^2+4v+3))=0

We get rid of parentheses

-v^2+5v-((7v^2+4v+3))-6=0


We calculate terms in parentheses: -((7v^2+4v+3)), so:

(7v^2+4v+3)

We get rid of parentheses

7v^2+4v+3

Back to the equation:

-(7v^2+4v+3)


We add all the numbers together, and all the variables

-1v^2+5v-(7v^2+4v+3)-6=0

We get rid of parentheses

-1v^2-7v^2+5v-4v-3-6=0

We add all the numbers together, and all the variables

-8v^2+v-9=0

a = -8; b = 1; c = -9;
Δ = b2-4ac
Δ = 12-4·(-8)·(-9)
Δ = -287
Delta is less than zero, so there is no solution for the equation